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Calculate Euler Number with Recursion

I recently went through several posts I had made on one of the development forums back then in 2005. I've found one of them interesting and wanted to repost it here. The question went like this:


"How can I calculate euler number with recursion ?"


Euler number (or e) can be calculated with the following formula in math:


sum = 1/0! + 1/1! + 1/2! + ... + 1/n!

Here one can notice the use of the Factorial function which can be implemented via recursion itself like so:


int Factorial(int n) 
{
    if (n == 0) 
    {
        return 1;
    }

    return n * Factorial(n - 1);
}

After we know how to implement Factorial we can implement Euler number using recursion as well:


double EulerNumber(int n) 
{
    if (n == 0) 
    {
        return 1;
    }

    return 1.0/Factorial(n) + EulerNumber(n - 1);
}

Enjoy :)


Related Posts:

Tuesday, March 11, 2008 4:01 AM

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